I2C: return error after failed write

The previous mechanism of retrying a failed write could become a
infinite blocking loop (until watchdog tiemout).

Also the array size is used to know how much data to write and verify
instead of a constant.

Change-Id: I8d2d090c5f4d1195f4c7eb29b3958a7bb05f56ec
This commit is contained in:
Kévin Redon
2018-07-24 09:54:12 +02:00
parent 57b60d23cf
commit a71a6f48cb

View File

@@ -70,8 +70,6 @@ const unsigned char __eeprom_bin[256] = {
#include "i2c.h"
static int write_hub_eeprom(void)
{
const unsigned int __eeprom_bin_len = 256;
int i;
/* wait */
@@ -79,16 +77,18 @@ static int write_hub_eeprom(void)
TRACE_INFO("Writing EEPROM...\n\r");
/* write the EEPROM once */
for (i = 0; i < 256; i++) {
for (i = 0; i < ARRAY_SIZE(__eeprom_bin); i++) {
int rc = eeprom_write_byte(0x50, i, __eeprom_bin[i]);
/* if the result was negative, repeat that write */
if (rc < 0)
i--;
if (rc < 0) {
TRACE_ERROR("Writing EEPROM failed at byte %u: 0x%02x\n\r",
i, __eeprom_bin[i]);
return 1;
}
}
/* then pursue re-reading it again and again */
TRACE_INFO("Verifying EEPROM...\n\r");
for (i = 0; i < 256; i++) {
for (i = 0; i < ARRAY_SIZE(__eeprom_bin); i++) {
int byte = eeprom_read_byte(0x50, i);
TRACE_INFO("0x%02x: %02x\n\r", i, byte);
if (byte != __eeprom_bin[i])